How much heat in joules and in calories is required to heat at 28.4g( 1 oz) ice cube from -23C TO 1.0C

1426.58 J  and 340.90 calories heat in joules and in calories is required to heat at 28.4g( 1 oz) ice cube from -23C TO 1.0C.

Explanation:

Data given:

mass = 28.4 gram

initial temperature = -23 degrees

final temperature = 1degress

change in temperature  ΔT = Tfinal - Tinitial

ΔT =  1 -(-23)

 ΔT = 24 degrees

specific heat capacity of ice cube c = 2.093 J/g C

Formula used:

q = mc ΔT

putting the values in the equation:

q= 28.4 x 2.093 x 24

  = 1426.58 J

ENERGY IN CALORIES:

340.90 calories is the energy is required in the process.

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