Calculate the volume occupied by 16.3 moles of nitrogen gas at 273 K and 101.3kPa

V= 366.3 L

Explanation:

Using the ideal gas law; PV = nRT

P= pressure = 101 kPa  , n =  Number of moles = 16.3 moles

V = Volume = ?               R= Gas constant =  8.31 kPa L/Mol K

T= Temperature = 273K

We make ''V'' the subject of the formular;

V = n R T/ P =  16.3mol  x 8.31 kPa. L / mol. K x 273 K

                                           101 kPa

                V  = 366.3 L

the answer is barium and copper bromide