225 J of heat energy were absorbed when a 35.0 g sample of iron was warmed. What was the change in temperature?

Question 3 options:

2.89°C

3536°C

0.070°C

14.3°C

14.3°C

Explanation:

q = m * c * ΔT

ΔT =

the specific heat of iron (c) is 0.450 J/g°C

ΔT = = =

cancel out stuff now

ΔT = = 14.3

12 is it do you think so

the answer is c i took the test