Calculate delta H for the reaction of sulfur dioxide with oxygen

DELTA H FOR THE REACTION OF SULFUR DIOXIDE WITH OXYGEN IS -197.8 KJ.

Explanation:

The letter "H" represents the enthalpy of a system. Enthalpy refers to the sum of the internal energy of a system plus the product of the system's pressure and volume. The delta symbol is used to represent change. Therefore, delta H represents the change in enthalpy of a system in a reaction.

∆H  = ∆Hf (products) - ∆Hf(reactants)

∆H = 2X ∆Hf(SO3) - [ 2 X ∆Hf(SO2) + ∆Hf(O2) ]

∆H = 2 X -395.7 - [ 2 X -296.8 + 0 ]  

elements in their standard state has zero ∆Hf

∆H = -791.4 + 593.6 = -197.8 kj

so answer is  –197.8 kJ