Fe(OH)3(s) Fe2O3(s)+H2O(g)

Explanation:

I guess the problem here is in balancing the equation;

  The expression given;

           Fe(OH)₃    →    Fe₂O₃    +    H₂O

In balancing any chemical equation, the law of conservation of matter comes to mind.

From the law we have been able to deduce that the amount of reactants and products formed are the same in any chemical reaction.

By virtue of this, we can balance any chemical equation.

let us take a,b and c as the numbers that will balance the equation;

           aFe(OH)₃    →    bFe₂O₃    +    cH₂O

Conserving Fe;    a  = 2b

                     O:    3a  = 3b + c

                      H: 3a   = 2c

let us assume that b = 1

                                a  = 2

                                 c  = 3

            2Fe(OH)₃    →    Fe₂O₃    +    3H₂O

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the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.