1. You find 25.0 g barium metal in the school chemistry storeroom. If you carefully reacted the barium the barium with 1.00 L of water, determine the concentration of the barium hydroxide solution produced. Assume that the resulting solution is 1.00 L.

0.182M Ba(OH)₂

Explanation:

The reaction of barium metal (Ba) with H₂O is:

Ba + 2H₂O → Ba(OH)₂ + H₂

25g of Ba are:

25g Ba × (1mol / 137.327g) = 0.182 moles of Ba. Based in the reaction, 1 mole of Ba produces 1 mole of Ba(OH)₂. That means you will produce 0.182 moles of Ba(OH)₂. If the whole volume of your solution is 1.00L, the concentration of barium hydroxide is:

0.182 moles of Ba(OH)₂ / 1.00L = 0.182M Ba(OH)₂

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