Consider the following unbalanced equation:
Li2S(aq) + Bi(NO3)3(aq) → LiNO3(aq) + Bi2S3(s)
If 20.5 moles of Li2S(aq) reacts with an excess of Bi(NO3)3(aq), what is the theoretical yield of LiNO3(aq) in moles?

41 moles

Explanation:

The balanced equation for the reaction is given below:

3Li2S + 2Bi(NO3)3 —> 6LiNO3 + Bi2S3

The theoretical yield of LiNO3 can be obtained as follow:

From the balanced equation,

3 moles of Li2S produced 6 moles of LiNO3.

Therefore, 20.5 moles of Li2S will produce = (20.5 x 6)/3 = 41 moles of LiNO3

Therefore, the theoretical yield of LiNO3 is 41 moles

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