A 1.78−L sample of hydrogen chloride (HCl) gas at 2.09 atm and 22°C is completely dissolved in 699 mL of water to form hydrochloric acid solution. Calculate the molarity of the solution. Assume no change in volume.

Explanation:

Hello,

In this case, it is firstly necessary to compute the dissolved moles of hydrogen chloride into the water as shown below:

Thus, the molarity is computed as shown below:

Wherein no change in volume is considered, therefore the volume of the solution was the same volume of water.

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you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6