A major component of gasoline is octane . When octane is burned in air, it chemically reacts with oxygen gas to produce carbon dioxide and water . What mass of "oxygen gas is consumed" by the reaction of 6.1 g of octane

10.608 grams oxygen.

Explanation:

The chemical formula of octane is and its molecular mass is 114.23 g/mol.

So, the number of moles in 6.1 g octane = = 0.053 moles

The chemical reaction of octane with oxygen has been written below in the balanced form -

+ =

From the stoichiometric coefficients of the above reaction we see that one mole of octane consumes moles of oxygen.

So, for 0.053 mole of octane the moles of oxygen consumed = = 0.663 moles oxygen

We know, the mass of one mole oxygen = 16 g

So, mass of 0.663 moles oxygen = 16 × 0.663 = 10.608 g

So, 6.1 g of octane will consume 10.608 g of oxygen.

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