A compound, C10H14, shows an IR peak at 825 cm-1. Its 1H NMR spectrum has peaks at delta 7.0 (4 H, broad singlet), 2.85 (1 H, septet, J=8 Hz), 2.28 (3 H, singlet), and 1.20 (6 H, doublet, J=8 Hz). Draw its structure in the window below.

The structure is that of p-Cymene as shown attached.

Explanation:

To solve the question, we note that at an IR peak at 825 cm⁻¹ we have either a tri-substituted alkenes or a para-di-substituted benzene.

The ¹H NMR spectrum peaks are at delta 7.0 which corresponds to an aromatic and with the 4 H broad singlet indicating that they are sharing two protons while being adjacent to a carbon with no protons. The peak at 2.85 with 1 H septet indicates methyl group with one proton attached to two equivalent alkyl groups with 3 protons each. The peak at 2.28 with three proton is equivalent to a methyl group attached to the aromatic ring while the peak at 1.2 with 6 protons are the 2 equivalent methly groups attached to a carbon with only one proton.

The structure is attached.

the molecules move in straight line until they collide with each other or with the walls of the container. collisions are perfectly elastic; when two molecules collide, they change their directions and kinetic energies, but the total kinetic energy is conserved.

explanation: