Over a 12.3 minuete period 5.13 E-3 moles of F2 gas effuses from a contaier. How many moles of CH4 gas could effuse from from the same container in the same period of time under the same conditions

Answer : The moles of methane gas could be,

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

or,

where,

= rate of effusion of fluorine gas

= rate of effusion of methane gas

= moles of fluorine gas =

= moles of methane gas = ?

= time = 12.3 min  (as per question)

= molar mass of fluorine gas  = 38 g/mole

= molar mass of methane gas = 16 g/mole

Now put all the given values in the above formula 1, we get:

Therefore, the moles of methane gas could be,

idk

explanation: