Consider the following balanced equation for the following reaction:
15O2(g) + 2C6H5COOH(aq) → 14CO2(g) + 6H2O(l)
Determine the amount of CO2(g) formed in the reaction if the percent yield of CO2(g) is 83.0% and the theoretical yield of CO2(g) is 1.30 moles.

The amount of carbon dioxide formed in the reaction is 47.48 grams

Explanation:

For the given chemical equation:

To calculate the actual yield of carbon dioxide, we use the equation:

Percentage yield of carbon dioxide = 83 %

Theoretical yield of carbon dioxide = 1.30 moles

Putting values in above equation, we get:

To calculate the number of moles, we use the equation:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 1.079 moles

Putting values in above equation, we get:

Hence, the amount of carbon dioxide formed in the reaction is 47.48 grams