To standardize a solution of NaOH before using it in a titration of an unknown acid, you dissolve 3.56 grams of potassium hydrogen phthalate (KHP) into 100 mL of H2O. You then titrate the KHP with your sodium hydroxide solution and reach the endpoint after adding 20.9 mL of NaOH. What is the molarity of your sodium hydroxide solution? (Molecular Mass of KHP = 204.22 g/mol)

The molarity of your sodium hydroxide solution is 0.813 M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

where,

n= moles of solute  

= volume of solution in ml = 100 ml

moles of solute (KHP)  =

According to the neutralization law:

where,

= molarity of KHP solution = 0.17 M

= volume of KHP  solution = 100 ml

= molarity of NaOH solution = ?

= volume of NaOH solution = 20.9 ml

= valency of KHP = 1

= valency of NaOH = 1

Thus the molarity of your sodium hydroxide solution is 0.813 M

answer; i believe that the correct answer is (a) potassium(k)

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"