A quantity of gas occupies a volume of 506 cm 3 at a temperature of 147 o C.
Assuming the pressure stays constant, at what temperature will the
volume of the gas be 604 cm 3 ?

228.3°C

Explanation:

Data obtained from the question include:

V1 (initial volume) = 506 cm3

T1 (initial temperature) = 147°C = 247 + 273 = 420K

V2 (final volume) = 604 cm3

T2 (final temperature) =?

The gas is simply obeying Charles' law because the pressure is constant.

The final temperature of the gas can be obtained by using the Charles' law equation V1/T1 = V2/T2 This is illustrated below:

V1/T1 = V2/T2

506/420 = 604/T2

Cross multiply to express in linear form as shown:

506 x T2 = 420 x 604

Divide both side by 506

T2 = (420 x 604) /506

T2 = 501.3K

Now let us convert 501.3K to a temperature in celsius scale. This is illustrated below:

°C = K - 273

°C = 501.3 - 273

°C = 228.3°C

Therefore, the temperature of the gas when the volume of the gas is 604 cm3 is 228.3°C

the answer is na (sodium)

elements make up everything, and they combine to make compounds.

the answer is c