354.4 g of chlorine gas (MW=70.9g/mol) is held in a vessel with a fixed volume of 70.0 L. What is the pressure of the gas in atmospheres if its temperature is 30.0 Celsius?

Explanation:P = 1.73atm

mole(n) = mass in grams/ molecular weight

n = 354.4/ 70.9

n=4.8717mol

From PV =nRT

P=nRT/V

P= 4.8717×0.0821×303/70

P=1.73atm

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.