When Na + O2 --> Na2O is balanced, what coefficient is in front of the Na?

Hey there!

Na + O₂ → Na₂O

Balance O.

2 on the left, 1 on the right. Add a coefficient of 2 in front of Na₂O.

Na + O₂ → 2Na₂O

Balance Na.

1 on the left, 4 on the right. Add a coefficient of 4 in front of Na.

4Na + O₂ → 2Na₂O

Our final balanced equation: 4Na + O₂ → 2Na₂O

Hope this helps!

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied