NEED ANSWER ASAP If the volume of a container of air is reduced by one half, what happens to the partial pressure of carbon dioxide within the container?
A. It is reduced by one half.
B. It is unchanged.
C. It is doubled.

The pressure of the container becomes doubled.

Explanation:

Boyle's law is one of the gas laws that is used to illustrate Ideal gas law.

This law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

Mathematically,

The equation given by this law is:

where,

are initial pressure and volume.

are final pressure and volume.

When the volume of the container is reduced to half, the equation becomes:

Putting values in above equation, we get:

Hence, the pressure of the container becomes doubled.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2