![\text{Rate}=k[Li][NaCl]](/tpl/images/0574/5230/1bc48.png)
For the chemical reaction, Li + NaCl <-- --> Na + LiCl, the rate law would be...
A...
Chemistry, 01.04.2020 01:11 sammybrain
For the chemical reaction, Li + NaCl <-- --> Na + LiCl, the rate law would be...
A. Rate = k[Li][NaCl]
B. Rate = k[Na] [LiCl]
C. Rate = k[Li] + [NaCl]
D. Rate = k[Na] + [LiCl]
Answers: 3
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