Chemistry, 01.04.2020 05:39 bbgrl3018

2NOCI (g)
→ 2NO(g) + Cl2 (g)
Problem:
Initially
the above reaction contains
0.50 M of NOCI,
0.00 M of NO,
0.00 M of C12.
Equilibrium Constant Kc = 1.6 (10^5)
What is the Equilibrium
Concentration of Cl2?

Answers: 1

Show answers

Answers

Answer from: mstrish71oteauw

0.0097 mol·L⁻¹

Explanation:

The balanced equation is

2NOCl ⇌ 2NO₂ + Cl₂

Data:

Your value of Kc is incorrect. It should be

Kc =1.6 × 10⁻⁵

[NOCl] = 0.50 mol·L⁻¹

[NO] = 0.00 mol·L⁻¹

[Cl₂] = 0.00 mol·L⁻¹

Calculations:

1. Set up an ICE table.

$\begin{array}{ccccccc}\rm \text{2NOCl}& \, \rightleftharpoons \, & \text{2NO} & +&\text{Cl}_{2} \\0.50 & &0.00 & & 0.00 & & \\-2x & & +2x & & +x & & \\0.50 -2x & & 0.00 + 2x & & 0.00 + x & & \\\end{array}$

2. Calculate the equilibrium concentrations

$K_{\text{c}} = \dfrac{\text{[NO]$^{2}$[Cl$_{2}$]}}{\text{[NOCl]}^{2}} = \dfrac{(2x)^{2}(x)}{(0.50 - 2x)^{2}} = 1.6 \times 10^{-5}\\\\4x^{3} = 1.6 \times 10^{-5}(0.50 - 2x)^{2}\\x^{3} = 4.0 \times 10^{-6}(0.50 - 2x)^{2}$

This is a cubic equation. Some calculators can solve cubic equations, but we can solve it by the method of successive approximations.

We will make changes to the right-hand side until the calculated value of x no longer changes,

(a) 1st approximation

Assume that 2x is negligible compared to 0.50. Then

$x = \sqrt [3] {4.0 \times 10^{-6}(0.50)^{2}} = 0.010$

(b) 2nd approximation

Assume that x= 0.010. Then

$x = \sqrt [3] {4.0 \times 10^{-6}(0.50 - 2\times 0.010)^{2}} = 0.0097$

(b) 3rd approximation

Assume that x= 0.0097. Then

$x = \sqrt [3] {4.0 \times 10^{-6}(0.50 - 2\times 0.0097)^{2}} = 0.0097$

No change, so x = 0.0097.

[Cl₂] = x mol·L⁻¹ = 0.0097 mol·L⁻¹

Check:

$\begin{array}{rcl}\dfrac{(2\times 0.0097)^{2} \times 0.0097}{(0.050 - 2 \times0.097)^{2}} & = & 1.6 \times 10^{-5}\\\\\dfrac{3.76 \times 10^{-4} \times 0.0097}{(0.050 - 0.0194)^{2}} & = & 1.6 \times 10^{-5}\\\\\dfrac{3.65 \times 10^{-6}}{(0.481)^{2}} & = & 1.6 \times 10^{-5}\\\\\dfrac{3.65 \times 10^{-6}}{0.231} & = & 1.6 \times 10^{-5}\\\\1.6\times 10^{-5} & = & 1.6 \times 10^{-5}\\\end{array}$

It checks.

Answer from: Quest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

Electrons are transferred from atoms of to atoms of this transfer makes the sodium atoms and the

Answer from: Quest

1. they vary with a higher number because boiling is way hotter than melting

Another question on Chemistry

Chemistry, 22.06.2019 05:00

Choose all the answers that apply. ionic compounds dissolve easily in water do not dissolve in water have low melting points have high melting points conduct electricity when melted

Answers: 1

Answer

Chemistry, 22.06.2019 15:20

Identify arrows pointing to bonding electrons. done h-0-0-h ) intro

Answers: 3

Answer

Chemistry, 22.06.2019 23:00

What is the chemical formula for dihydrogen monoxide

Answers: 2

Answer

Chemistry, 23.06.2019 00:00

How many moles of water are created if 3 moles of hydrogen react completely with excess oxygen?