In a lab, 2.20 L of gas is collected over water at a temperature of 30 degrees C and a total pressure of 735.43 mmHg. Find the volume that the dry nitrogen of gas would occupy at STP.

Volume of nitrogen at STP  = 1.92 L

Explanation:

Given data:

Initial volume of gas = 2.20 L

Initial temperature = 30°C (30+273 = 303 k)

Initial pressure = 735.43 mmHg (735.43/760 = 0.97 atm)

Final volume = ?

Final pressure = 1 atm

Final temperature = 273 K

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 0.97 atm × 2.20 L × 273 K / 303 K × 1 atm

V₂ = 582.58 atm .L. K / 303 K.atm

V₂ = 1.92 L

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