Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 56. g of butane is mixed with 138. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to significant digits.

86,9g

Explanation: Molar mass of C is 12, of H it's 1. Molar mass of butane is 4*12 + 10*1 (C4H10) = 58g/mol. So 56g of butane is (56/58) =0,9655mol.

2C4H10 + 13O2 = 8 CO2 + 10 H2O.

From 2 mol butane you can make 10 mol H2O.

So if you only have 0,9655 mol butane, then that will give you a maximume of (0,9655/2)*10=4,828 mol water. 1 mol water's mass is 18g. So 4,828 mol is 4,828*18=86,89g.

a c d and f

just finished the assignment

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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