A student is using the periodic table to find information for a report on elements. One of the statements about fluorine in her report contains an error. Find the error, and write your replacement for the error beneath the statement. Flourine is a halogen in group 17. Its chemical symbol is F. It is atomic number 9 and has 7 valence electrons. Flourine has a low reactivity compared to many other elements.

Flourine has a low reactivity compared to many other elements.

Explanation:

Obviously the wrong information about fluorine from the given choices is that it has a low reactivity compared to many other elements.

Fluorine is the most reactive non-metal with a high electronegativity value. It freely and easily combines with other substances to attain a stable configuration.

This element require just one electron to have a complete octet. This is why it is highly reactive. Flourine has the most oxidizing power of the halogens.

Other given facts are correct about flourine.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !