In a laboratory investigation, an HCl(aq) solution with a pH value of 2 is used to determine the molarity of a KOH(aq) solution. A 7.5-milliliter sample of the KOH(aq) is exactly neutralized by 15.0 milliliters of the 0.010 M HCl(aq). During this laboratory activity, appropriate safety equipment is used and safety procedures are followed. 1. Determine the pH value of a solution that is ten times less acidic than HCl (aq) solution.2. State the color of the indicator bromocresol green if it is added to a sample of the KOH(aq).3. Complete the equation for the reaction: HCl + KOH--> + .4. How the correct numerical setup to calculate the molarity of the KOH solution. 5. Explain in terms of aqueous ions, why 15.0mL of 1.0M HCl(aq) is a better conductor of electricity than 15.0mL of 0.010M HCl(aq) solution.