A gas sample occupies 8.77 L at 20 degrees Celsius. What is the pressure in atm, given that there are 1.45 moles of gas in the sample?

3.88 atm  is the pressure in atm, given that there are 1.45 moles of gas in the sample.

Explanation:

Given that:

Volume of the gas sample V = 8.77 litres

temperature of the gas sample T = 20 degrees OR 293.15 K

number of moles of the gas = 1.45

R (Gas constant) = 0.08021 L.atm/mole K

Pressure of the gas = ?

The equation for ideal gas will be used here to calculate the pressure of the gas:

PV = nRT

the equation is rewritten as:

P=

P =

P = 3.88 atm

1.45 moles of the gas at given conditions would have pressure of  3.88 atm.

b

explanation:

mitosis

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.