How many milliliters of 0.300 M nitric acid are required to react completely with 3.25 g of calcium carbonate?
2 HNO3(aq) + CaCO3(s) H2O(l) + CO2(g) + Ca(NO3)2(aq)

A. 216
B. 32.5
C. 0.216
D. 108
E. 1950

Hence, correct answer is option A.

Explanation:

Mass of calcium carbonate = 3.25 g

Moles of calcium carbonate =

According to reaction, 1 mole of calcium carbonate reacts with 2 moles of nitric acid then 0.0325 moles of calcium carbonate will react with :

Moles of nitric acid = 0.0650 mol

Volume of the nitric acid solution = V

Molarity of the nitric solution = 0.300 M

1 L = 1000 mL

0.216 L = 0.216 × 1000 mL = 216 mL

Hence, correct answer is option A.

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e

b. examine and describe cells