Calculate the number of grams of Fe that are produced when 57 grams of FeO is reacted with excess aluminum in the following reaction: 2Al(s) + 3FeO(s) -> 3Fe(s) + Al₂O₃(s)

Mass of Fe produced = 44.7 g

Explanation:

Given data:

Mass of Fe produced in gram = ?

Mass of FeO react = 57 g

Solution:

Chemical equation:

2Al + 3FeO  →  3Fe + Al₂O₃

Number of moles of FeO:

Number of moles = mass/ molar mass

Number of moles = 57 g/ 71.844 g/mol

Number of moles = 0.8 mol

Now we will compare the moles of Fe with FeO from balance chemical equation.

                    FeO          :          Fe

                       3            :           3

                    0.8            :          0.8

Mass of Fe:

Mass = Mass × molar mass

Mass = 0.8 mol ×  55.845 g/mol

Mass = 44.7 g

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