What is the final chemical equation from the following intermediate chemical equations? 2 equations. First: upper P subscript 4 upper O subscript 6 (s) right arrow upper P subscript 4 (s) plus 3 upper O subscript 2 (g). Second: upper P subscript 4 (s) plus 5 upper O subscript 2 (g) right arrow upper P subscript 4 upper O subscript 10 (s). Upper P subscript 4 upper O subscript 6 (s) plus 2 upper O subscript 2 (g) right arrow upper P subscript 4 upper O subscript 10 (s). Upper P subscript 4 upper O subscript 6 (s) plus 8 upper O subscript 2 (g) right arrow 2 upper P subscript 4 (s) plus upper P subscript 4 upper O subscript 10 (s). Upper P subscript 4 upper O subscript 6 (s) plus 15 upper O subscript 2 (g) right arrow upper P subscript 4 (s) plus upper P subscript 4 upper O subscript 10 (s). Upper P subscript 4 upper O subscript 6 (s) StartFraction 5 over 3 EndFraction upper O subscript 2 (g) right arrow upper P subscript 4 upper O subscript 10 (s).

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.

(b) which contains higher levels of vitamin b, oranges or spinach?

explanation:

you can eliminate a, c, and d because they are questions based on opinions.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally