Calculate the mass of ZnCl2 produced by the reaction of 49.8 grams of H2. Zn + 2HCl ZnCl2 + H2

3300.85 g

Explanation:

Given data:

Mass of ZnCl₂ produced = ?

Mass of H₂ produced = 49.8 g

Solution:

Chemical equation:

Zn + 2HCl     →    ZnCl₂ + H₂

Number of moles of  H₂:

Number of moles = mass/molar mass

Number  of moles = 49.8 g/ 2.056 g/mol

Number  of moles = 24.22 mol

Now we will compare the moles of H₂ with ZnCl₂ form balance chemical equation.

                         H₂              :              ZnCl₂

                          1                :                   1

                        24.22         :              24.22

Mass of ZnCl₂:

Mass = number of moles × molar mass

Mass =  24.22 × 136.286 g/mol

Mass = 3300.85 g

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.