How many moles of aluminum oxide are in a sample with a mass of 204

(204 g)/(101.96 g/mol) = 2.001 mol. 2(2.001) = 4.002 moles of aluminium in the sample

Explanation:

108 g

Explanation:

The molar mass of aluminium is 26.98 g/mol; the molar mass of (atomic) oxygen is 16.00 g/mol.

1 mole of Al₂O₃ therefore has a mass of 2(26.98) + 3(16.00) = 101.96 g.

Divide this into the given mass, to find the number of moles here:

(204 g)/(101.96 g/mol) = 2.001 mol.

There are 2 moles of aluminium per mole of aluminium oxide, so there are

2(2.001) = 4.002 moles of aluminium in the sample.

Then there are (4.002 mol)(26.98 g/mol) = 107.97 g of Al. Since the given mass has only 3 significant figures, round this answer to 108 g.

why is cellular respiration important for homeostasis?

it changes food into energy that the organism can use.

which of the following is most likely to happen if a cell is not able to divide?

the cell will not be replaced when it is damaged.

explanation: