A ballon is blown up to a volume of 0.39 L at 74 F the ballon sits in a hot car which reaches 102 F.
Assuming constant pressure what is the new volume of the ballon?

V₂ = 0.41 L

Explanation:

Given data:

Initial volume of balloon = 0.39 L

Initial temperature = 74 F°

Final temperature = 102 F°

Final volume = ?

Solution:

First of all we will convert the temperature into K.

(74 F° - 32) ×5/9+273.15 = 296.483 K

(102F° - 32) ×5/9+273.15 =312.039 k

Now we will apply the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 0.39 L × 312.039 K / 296.483 K

V₂ = 121.7 L.K /296.483 K

V₂ = 0.41 L

fe 55.85 g/mol and h2o 18.02 g/mol.

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