Suppose you place 125 g of aluminum in a calorimeter with 1,000 g of water. The water changes temperature by 2 °C and the aluminum changes temperature by –74.95 °C.

Water has a known specific heat capacity of 4.184 J/g °C. Use the specific heat equation to find out how much heat energy the water gained (q).

The amount of heat gained by the water is 8368 J

Explanation:

To calculate the amount of heat absorbed, we use the equation:

where,

q = amount of heat absorbed = ?

m = mass of water = 1000 g

C = specific heat capacity of water = 4.184 J/g°C

= change in temperature = 2°C

Putting all the values in above equation, we get:

Hence, the amount of heat gained by the water is 8368 J

a c d and f

just finished the assignment

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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