ES
How many milliliters of water should be added to
50.0 mL of a 1.0 M CaBr2 solution to create a 0.25
M solution?

150mL

Explanation:

First, let us calculate the volume of the diluted solution. This is illustrated below:

Information obtained from the question include:

V1 (initial volume) = 50mL

C1 (initial concentration) = 1M

C2 (final concentration) = 0.25M

V2 (final volume) =.?

The volume of the diluted solution can be obtained using the dilution formula C1V1 = C2V2 as shown below:

C1V1 = C2V2

1 x 50 = 0.25 x V2

Divide both side by 0.25

V2 = 50/0.25

V2 = 200mL

The volume of the diluted solution is 200mL.

Now, to obtain the volume of the water added to the solution, we'll simply subtract the initial volume from the final volume as shown below

Volume of water added = V2 - V1

Volume of water added = 200 - 50

Volume of water added = 150mL

Therefore, the volume of water added is 150mL

answer: h+ its less than oh

explanation:

1 is the answer to this problem