Sodium carbonate is a reagent that may be used to standardize acids. In such a standardization it was found that a 0.498-g sample of sodium carbonate required 21.3 mL of a sulfuric acid solution to reach the endpoint for the reaction.

Na2CO3 (aq) + H2SO4 (aq) → H2O (l) + CO2 (g) + Na2SO4 (aq)

What is the molarity of the H2SO4?

The molarity of H2SO4 is 0.221 M

Explanation:

Step 1: Data given

Mass of sodium carbonate (Na2CO3) = 0.498 grams

Molar mass Na2CO3 = 105.99 g/mol

Volume of sulfuric acid (H2SO4) = 21.3 mL = 0.0213 L

Step 2: The balanced equation

Na2CO3 (aq) + H2SO4 (aq) → H2O (l) + CO2 (g) + Na2SO4 (aq)

Step 3: Calculate moles Na2CO3

Moles Na2CO3 = 0.498 grams / 105.99 g/mol

Moles Na2CO3 = 0.00470 moles

Step 4: Calculate moles H2SO4

For 1 mol Na2CO3 we need 1 mol H2SO4 to react and produce 1 mol H2O, 1 mol CO2 and 1 mol Na2SO4

For 0.00470 moles Na2CO3 we need 0.00470 moles H2SO4 to react

Step 5: Calculate molarity of H2SO4

Molarity H2SO4 =moles H2SO4 / volume

Molarity H2SO4 = 0.00470 / 0.0213 L

Molarity H2SO4 = 0.221 M

The molarity of H2SO4 is 0.221 M

what is the question here. i think you messed up.

one negative thing it that it can kill water animals. another negative thing is it can cause the destruction of ecosystem. one way water pollution can be reduced is to conserve energy.