A 15.0 L tank of gas is contained at a high pressure of 8.20x10 4 torr. The tank is opened and the gas expands into an empty chamber with a volume of 6.00x10 4 L. Calculate the new pressure of the gas.

P₂ = 20.5 torr

Explanation:

Given data:

Volume of tank = 15.0 L

Pressure of tank = 8.20×10⁴ torr

Final volume of tank = 6.00×10⁴ L

Final pressure = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

8.20×10⁴ torr  ×  15.0 L = P₂ × 6.00×10⁴ L

P₂ = 8.20×10⁴ torr  ×  15.0 L / 6.00×10⁴ L

P₂ = 123×10⁴ torr.L/ 6.00×10⁴ L

P₂ = 20.5 torr

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.