What is the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide

[KI] = 0.25 M

Explanation:

Solute: KI

Mass of solute: 0.50 mol . 166 g / 1mol = 83 g

Our solution volume is 2L

Molarity is a kind of concentration, defined as the moles of solute contained in 1L of solution. It is the most common concentration for all solutions while there are any other kind, for example molality, mole fraction or ppm.

In this case molarity (mol/L) is 0.5 mol /2L = 0.25 M

In conclussion, solution is 0.25 molar whichs is the same to say, that 0.25 moles of potassium iodide are contained in 1L of solution.

With the data given, we can also make a rule of three:

2L of solution contain 0.5 moles of KI

Then, 1L of solution may contain (0.5 . 1) /2 = 0.25 moles of Ki

0.25mol/L

Explanation:

Data obtained from the question include:

Mole of solute (KI) = 0.50 mol

Volume of solution = 2L

Molarity =?

Molarity is simply the mole of solute per unit litre of the solution. It is represented mathematically as:

Molarity = mole of solute /Volume of solution

Molarity = 0.50mol/2L

Molarity = 0.25mol/L

Therefore, the molarity of the solution is 0.25mol/L

i believe it is c.) 1575 j.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :