2HCI + Na, so, - 2NaCl + H, so,
How much H, so, is produced when 40.0g of HCl react?
ОА 107.60
в 36.5 g
с 08.1 g
O D53.8 g

None of the options are correct.

The correct answer is 1.10g

Explanation:

First, we'll begin by balancing the equation given above. This is illustrated below:

2HCl + 2Na —> 2NaCl + H2

Next, let us calculate the mass of HCl that reacted and the mass of H2 produced from the balanced equation. This is illustrated below:

Molar Mass of HCl = 1 + 35.5 = 36.5g/mol

Mass of HCl from the balanced equation = 2 x 36.5 = 73g

Molar Mass of H2 = 2x1 = 2g/mol

Now we can easily find the mass of H2 produced when 40g of HCl reacted as shown below:

From the balanced equation,

73g of HCl produced 2g of H2.

Therefore, 40g of HCl will produce = (40 x 2)/73 = 1.10g of H2.

From the calculations made above,

40g of HCl produced 1.10g of H2

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.