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What is the molarity of the solution when 145 g NaCl is dissolved in water
to make 2.5 L of solution?

The molarity of the solution is 0,99M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g1 mol NaCl

145 g x= (145 g x 1 mol NaCl)/58, 5 g= 2,48 mol NaCl

2,5 L solution 2, 48 mol NaCl

1 L solutionx= (1 L solutionx 2, 48 mol NaCl)/2,5L solution

x=0,99 mol NaCl---> The solution is 0,99 molar (0,99 M)

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2b2t

explanation:

2b2t

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.