7. A sample of argon gas has a volume of 0.43 mL at 24 C. At what temperature in Celsius
will it have a volume of 0.57 mL?

120.55 °C

Explanation:

Given data:

Initial volume of gas = 0.43 mL

Final volume of gas = 0.57 mL

Initial temperature = 24°C (24+273 = 297 k)

Final temperature = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁/V₁  

T₂ = 0.57 mL × 297 K / 0.43 mL

T₂ = 169.29 mL.K / 0.43 mL

T₂ = 393.7 K

Temperature in celsius:

393.7 K - 273.15 = 120.55 °C

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but