What is the volume of 23.4 grams of nitrogen gas at 750 mmHg and 28 degrees C

V = 20.97 L

Explanation:

Given data:

Mass of nitrogen = 23.4 g

Pressure of gas = 750 mmHg (750/760 = 0.99 atm)

Temperature of gas = 28°C (28+273= 301K)

Volume of gas = ?

Solution:

First of all we will calculate the number  of moles of gas.

Number of moles = mass / molar mass

Number of moles = 23.4 g/ 28 g/mol

Number of moles = 0.84 mol

Now we will calculate the volume:

PV = nRT

V = nRT/P

R = general gas constant = 0.0821 atm.L/mol.K

V = 0.84 mol× 0.0821 atm.L/mol.K× 301 K /  0.99 atm

V = 20.76 L/0.99

V = 20.97 L

mention the spill to the teacher clean the area and throw the broken pieces away

explanation:

c is the answer because when something is left after something evaporates that shows the chemical change.