A conical flask has a volume of 71.9 mL. It is filled with water vapour at a pressure of 1053.8 kPa and a temperature of 738 K. Determine the mass of
water in the conical flask.
Select one:
O a. 0.363 g
O b.0.183 g
O c.0.129 g
O d. 0.222 g

d. 0.222 g

Explanation:

Given parameters:

volume of water  = 71.9mL  = 0.0719L

pressure  = 1053.8kPa = 10.4atm

temperature  = 738K

Unknown:

mass of water  = ?

Solution:

To find the mass of water, we need to obtain the number of moles from the given parameters.

This can be done using the ideal gas law;

              PV  = nRT

where P is the pressure

          V is the volume

           n is the number of moles

           R is the gas constant

           T is the temperature

     Input the parameters to find n;

          10.4 x 0.0719  = n x 0.082 x 738

                  n  = 0.012moles

Mass of water vapor  = number of moles x molar mass

          molar mass of H₂O  = 2 + 16  = 18g/mol

Mass of water vapor  = 0.012 x 18 = 0.22g

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2