Chemistry, 03.04.2020 19:21 neonbluefaith
The decomposition of sulfonyl chloride, SOCl2 is a first order reaction with a half life of 8.75 hours. Calculate the concentration of SOCl2 after 17.0 hours have passed in an experiment where the initial concentration of sulfonyl chloride was .0837M.
Answers: 1
![[SOCl_2]=0.0218M](/tpl/images/0580/4335/612b0.png)
![\dfrac{d[A]}{dt}=-k[A]](/tpl/images/0580/4335/ee892.png)
![[A]=[A_0]e^{-kt}](/tpl/images/0580/4335/c121d.png)
![[SOCl_2]=0.0837M\cdot e^{-0.0792168h^{-1}\times 17.0h}](/tpl/images/0580/4335/71b3f.png)
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The decomposition of sulfonyl chloride, SOCl2 is a first order reaction with a half life of 8.75 hou...
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