Approximately 0.5 M KOH by diluting 20 mL of 6 M KOH into the appropriate volume of distilled water. You may use a 100-mL graduated cylinder repeatedly to reach your final volume. Show your calculations here: Final volume: (Store this solution in the provided bottle; label the bottle with your name and "0.5M KOH") b. Approximately 0.5 M HCI by diluting 5 mL of 6 M HCI into the appropriate volume of distilled water. You may use a 100-mL graduated cylinder to me It doesn't need to be exact. Show your calculations here: Final volume: c. Put enough solid NaCI to cover the bottom curve of a large test tube. Dissolve in about 15 mL of distilled water. 47

the ratio of the conjugate base to the acid required to attain the desired ph.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.