NEED HELP WITH CHEM :)
What volume of a 3.70 M NaCl solution is needed for a reaction that requires 118 g of NaCl?

volume of solution L =0.54 L

Explanation:

Given data:

Molarity of NaCl solution = 3.70 M

Mass of NaCl = 118 g

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/ molar mass

Number of moles = 118 g/ 58.5 g

Number of moles = 2 mol

Now we will calculate the volume from molarity formula:

Molarity = number of moles / volume of solution L

3.70 M = 2 mol / volume of solution L

volume of solution L = 2 mol / 3.70 M

volume of solution L =0.54 L