The exit gas from an alcohol fermenter consists of an air–CO2 mixture containing 10 mol% CO2 that is to be absorbed in a 5.0-N solution of triethanolamine, containing 0.04 mol CO2 per mol of amine solution. Assume that the column operates isothermally at 25∘C, the exit liquid contains 78.4% of the CO2 in the feed gas to the absorber, and absorption is carried out in a six-theoretical-plate column. Then use the equilibrium data below to calculate (a) exit-gas composition and (b) moles of amine solution required per mole of feed gas.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

idk what the question is about

може ли да зареждате повече информация, моля