Freezing point formula is Molarity * depression constant. And for this specific problem, you should get 4.8 as the result but since the freezing point is always negative, then the answer should be -4.8. The correct answer between all the choices given is the last choice or letter D. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.
D.) -4.8 °C
The formula used for depression in freezing point is:
= change in freezing point
= freezing point constant =
Thus the freezing point of the solution is .
2. d. -4.8 degree Celsius
3. a. Each solution has the same number of relative particles of solute per kilogram of solvent.
1) Water's structure allows for the formation of multiple hydrogen bonds with other molecules, including itself.
2) -4.8 °C
3) Each solution has the same number of relative particles of solute per kilogram of solvent.
1) the hydrogen attached to oxygen (a highly electronegative oxygen atom) thus is able to form hydrogen bond with other highly electronegative elements F,O and N. Due to this water has high boiling point as compared to other hydrides mentioned.
2) the freezing point depression is related to molality as:
Depression in freezing point = Kf X molality
depression in freezing point = 1.86 X 2.6 = 4.836
So the freezing point of aqueous solution = -4.836 °C
3) The colligative property depends upon the number of non volatile solute particles and not on nature of molar mass.
Thus both solution exhibit same collgative properties as we have taken one mole of each.