How many representative particles are in 1.45 g of a molecular compound with a molar mass of 237 g?

3.683×10^21 particles

Explanation:

Number of particles in a substance = (mass of the substance/molar mass of the substance)×Avogadro's number

Given;

Mass of compound =1.45g

Molar mass of compound =237g

Avogadro's number=6.02×10^23

Therefore, number of particles = (1.45/237)×6.02×10^23

=3.683×10^21 particles

3.68•10^21 particles (correct to 3SF)

Explanation:

1.45 • xg molecular compound • 1mol/237g • (6.02•10^23)/ 1 mol = 3.6831•10^21 representative particles

*6.02•10^23 is Avagadro's number

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72