A sample of an unknown gas effuses in 12.5 min. An equal volume of H2 in the same apparatus under the same conditions effuses in 2.42 min. What is the molar mass of the unknown gas

53.4 gMol-1

Explanation:

Let the mass of the unknown gas be M

Let the molar mass of hydrogen gas be 2×1=2gMol-1

Time for diffusion of unknown gas = 12.5 min

Time for diffusion of hydrogen= 2.42 min

From Graham's law:

t1/t2=√M1/M2

Hence:

2.42/12.5= √2/M

Hence M= 53.4 gMol-1

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)