Calculate OH- given .010 M h+

(OH-)=1x10^-12 M

Explanation:

Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:

(H3O+) x (OH-) = 1x10^-14

(0,010) x (OH-)= 1x10^-14

(OH-)=1x10^-14/(0,010)

(OH-)=1x10^-12 M

i think it is true since you can test the answer and can use observations to complete it.

so what is the problem with your lab report and whats the subject of the lab report? i will you