How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?

a
0.001 mL
b
none of the above
c
10 mL
d
0.10 mL

V₁  = 10 mL

Explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁  =  0.10 M×300.0 mL

3.0 M ×V₁  = 30 M.mL

V₁  = 30 M.mL /3.0 M

V₁  = 10 mL

your answer would be a. 12.5 kg

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.