How many calories must be absorbed by 20.0 g of water to increase its temperature from 383.0 C to 303.0 C

1600 calories

Explanation:

Data obtained from the question include:

M (mass of water) = 20g

T1 (initial temperature) = 383°C

T2 (final temperature) = 303°C

ΔT (change in temperature) = T1 - T2 = 383 - 303 = 80°C

C (specific heat capacity of water) = 1 calorie/g°C

Q (heat) =?

Using the the equation Q = MCΔT, the heat in calories absorbed by the water can be obtained as follow:

Q = MCΔT

Q = 20 x 1 x 80

Q = 1600 calories

Therefore, the heat absorbed by the water is 1600 calories

geosphere and hydrosphere.

this is because the geosphere has to do with geological events, while the hydrosphere controls all water on earth.